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Make 500ml of TE containing 10nM Tris and 1nM EDTA

Make 500ml of TE containing 10nM Tris and 1nM EDTA

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Answer #1

as we know V1S1=V2S2

V1 =Initial vol of stock solution needed

S1= initial concentration of stock solution ( 1 M tris cl, 0.5 M EDTA )

V2= final volume of desired solution

S2=  final concentration of desired solution( 10nM tris cl, 1nM EDTA )

in case of tris-cl

V1S1=V2S2   V1S1=V2S2

V1 * 109 nM = 5* 108 nl * 10nM V1 * 5* 108 nM = 5* 108 nl * 1nM

V1 = 0.5 nl V1 = 1 nl

so for 500ml TEcontaining 10nM Tris and 1nM EDTA, one have to add 0.5nl tris (1M), 1nl EDTA (0.5M) in 499.9999985 ml distilled water

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