Question

Suppose alleles A1,A2,A3, and A4 are additive in their effects, and the homozygote fitnessesare A1A1: 0.8, A2A2: 0.6, A3A3: 0.4, and A4A4: 0.2. What are the heterozygote fitnesses? I fall of the alleles are of equal frequency, what is the mean fitness for this locus?

Answer #1

As the alleles are additive and provided homozygote fitness

A1A1 = 0.8

A2A2 = 0.6

A3A3 = 0.4

A4A4 = 0.2

Heterozygotes will be A1A2, A1A3, A1A4, A2A3, A2A4, A3A4

A1A2 = 0.8/2 x 0.6/2 = 0.12

A1A3 = 0.8/2 x 0.4/2 = 0.08

A1A4 =0.8/2 x 0.2/2 = 0.04

A2A3 =0.6/2 x 0.4/2 = 0.06

A2A4 =0.6/2 x 0.2/2 =0.03

A3A4 = 0.4/2 x 0.2/2 =0.02

Mean fitness for this locus = (0.8/2 + 0.6/2 + 0.4/2 + 0.2/2)/4 =1/4= 0.25

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must show your work for calculations and type the correct answers
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digits. Partial credit will be given for using the correct
equations, but getting the wrong answer. Minimal credit (a quarter
of possible points) will be given for providing answers with no
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