Question

1. Conduct a dihybrid cross of pea plants with the following combination of traits: Parent 1—Tall...

1. Conduct a dihybrid cross of pea plants with the following combination of traits: Parent 1—Tall plant with white flowers (pure breeding); Parent 2—Dwarf plant with purple flowers (pure breeding). i) What are the genotypes of the parents? ii) What are the genotypes of their gametes? iii) Portray a cross and determine the F1 generation. Use a Punnett’s square. What are the genotypes and phenotypes of their offspring? iv) Conduct a F2 cross with the offspring. What are the genotypes and phenotypes of the offspring and their ratios.

Homework Answers

Answer #1

Parent 1 (TTpp) x Parent 2 (ttPP)-----P1

Tp                      tP --------Gametes

TtPp (tall, purple)------F1

TtPp x TtPp (self cross)

TP

Tp

tP

Tp

TP

TTPP (tall, purple)

TTPp (tall, purple)

TtPP (tall, purple)

TtPp (tall, purple)

Tp

TTPp (tall, purple)

TTpp (tall, white)

TtPp (tall, purple)

Ttpp (tall, white)

tP

TtPP (tall, purple)

TtPp (tall, purple)

ttPP (dwarf, purple)

ttPp (dwarf, purple)

tp

TtPp (tall, purple)

Ttpp (tall, white)

ttPp (dwarf, purple)

ttpp(dwarf, white)

F2 phenotypic ratio:

Tall, purple : Tall, white : Dwarf, purple : Dwarf, white = 9:3:3:1

Genotypic ratio:

TTPP=1

TTPp = 2

TtPP = 2

TtPp = 4

TTpp = 1

Ttpp = 2

ttPP = 1

ttPp = 2

ttpp = 1

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