Question

Question 11 pts

________________ is a specific version of a gene on a homologous chromosome that has a corresponding version of a similar gene on a homologous chromosome. For example, hair color gene (ie. red from mom) will be on one homologous chromosome and a possibly different version of hair color gene (ie. black from dad) will be on the other corresponding homologous chromosome.

chromosome

allele

chromatin

genome

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Question 21 pts

A ___________ is how you write the alleles found for a gene on homologous chromosomes.

Bb

genotype

BB

bb

all of the above

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Question 31 pts

Which of the following is a heterozygous genotype?

BB

Bb

bb

none of the above

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Question 41 pts

If both parents give the same alleles, or versions of the genes, then this is called _______________.

homozygous

heterozygous

phenotype

type locality

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Question 51 pts

____________ is the expressed version of the two alleles, or what you see physically.

heterozygous

genotype

phenotype

homozygous

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Question 61 pts

__________ is a homozygous recessive genotype.

BB

Bb

bb

blue

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Question 71 pts

If both parents are heterozygotes (Bb), what is the probability that their offspring will have a brown phenotype or have brown eyes?

25%

50%

75%

100%

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Question 81 pts

If both parents are heterozygotes (Bb), what is the probability that their offspring will have a heterozygous genotype?

25%

50%

75%

100%

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Question 91 pts

If the mother is homozygous dominant for brown eyes, and the dad is a heterozygote, what is the probability of producing a blue phenotype in the offspring?

25%

50%

75%

100%

0%

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Question 101 pts

If the mother is homozygous dominant for brown eyes, and the dad is a heterozygote, what is the probability of producing a homozygous dominant offspring?

25%

50%

75%

100%

0%

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Question 111 pts

When crossing two heterozygous plants with incomplete dominance for Red and White, what is the probability that they will have pink offspring?

25%

50%

75%

100%

0%

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Question 121 pts

What is the probability of having a child with B blood type, from parents who have AB and A0?

25%

50%

75%

100%

0%

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Question 131 pts

If the alleles for different traits (eye and hair color) are on different chromosomes, then during anaphase of meiosis I and II, the chromosomes or eye and hair color can end up in different gametes. This is called _________________.

linked traits

incomplete dominance

independent assortment

complete dominance

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Question 141 pts

In a dihybrid cross for brown/blue eyes and big/little teeth, what is the probability of having a big tooth, brown eyed child?

9/16

3/16

1/16

0%

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Question 151 pts

The 22 pairs of chromosomes in a human nucleus that do not code for gender are called _________________.

body chromosomes

sex-linked

autosomal

autolysal

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Question 161 pts

If the 23rd pair of chromosome's genotype is "XY" then the phenotype is a __________ and if the 23rd pair's genotype is "XX" then the phenotye is a ________________.

female, male

male, female

male, gender neutral

gender neutral, female

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Question 171 pts

Which sex determines whether the offpsring are male or female?

The male can donate either an X or a Y, so determines the sex.

The male can donate either an X or a X, so determines the sex.

The female can donate either an X or a Y, so determines the sex.

The female can donate either an X or a X, so determines the sex.

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Question 181 pts

If a female is a carrier for hemophilia (XXh), her phenotype will be ___________.

hemophilia

normal blood clotting

color blind

normal color vision

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Question 191 pts

If a male's phenotype is hemophilia, he got it from his _______________.

father

mother

mother and father

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Question 201 pts

If a female's phenotype is hemophilia, then she got it from her ________________.

father

mother

mother and father

Answer 1

11). Allele

Explanation:

Alternative forms of gene are called alleles.

21). Genotype

31). Bb

Explanation:

BB = homozygous dominant genotype

Bb = heterozygous genotype

bb = homozygous recessive genotype

41). Homozygous

51). Heterozygous

61). bb

71). 75%

Explanation:

	B	b
B	BB (brown)	Bb (brown)
b	Bb (brown)	bb ( blue)

Brown = 3/4 or 75%

Blue = 1/4 or 25%

BB = 1/4; Bb = 1/2; bb= 1/4

81). 50%

91). 0%

Explanation:

	B
B	BB (brown)
b	Bb (brown)

No blue phenotype.

101). 50%

111). 50%

Explanation:

RW (pink) x RW (pink)

	R	W
R	RR (red)	RW (pink)
W	RW (pink)	WW (white)

Red = 25%

Pink= 50%

White= 25%

121). 25%

Explanation:

IAIB (AB) x IAIO (A)----- Parents

	IA	IO
IA	IAIA ( A type)	IAIO (A type)
IB	IAIB (AB type)	IBIO (B type)

A type= 50%

AB type= 25%

B type= 25%