Question

On a separate sheet of paper, plug in the following values for p
and q into the Hardy-Weinberg equation
(p^{2}+2pq+q^{2}=1):

p=0.5, q=0.5

p=0.6, q=0.4

p=0.7, q=0.3

p=0.8, q=0.2

p=0.9, q=0.2

p=1.0, q=0.0

You have just modeled genetic drift acting on a population.
After you have plugged these values in, what trend do you see with
regards to the frequencies of the homozygous q (q^{2}) and
heterozygous (2pq) genotypes? What does this tell you about genetic
drift?

Answer #1

P^{2} |
2PQ | Q2 | ||

1 | 25% | 50% | 25% | |

2 | 36% | 48% | 16% | |

3 | 49% | 42% | 9% | |

4 | 64% | 32% | 4% | |

5 | 81% | 36% | 4% | |

6 | 100% | 0% | 0% |

As we can see that value of pq and q2 are decreasing... This signifies the gene frequency is changing due to genetic drift. There are only homozygous p individuals left and entire population having q allele has either migrated or due to change in environmental condition or any natural calamity has led to complete eradication of population having q allele.

Use the equation for Hardy-Weinberg equilibrium for the
following questions. p + q = 1 p2 + 2pq + q2 = 1
In domestic cats, the allele for short hair (L) is dominant and
the allele for long hair (l) is recessive. You are studying a
population of cats found on Iwato Island and have determined that
the frequency of the recessive long hair allele is q = 0.3.
A) What is the frequency of the dominant allele for short...

p+q =1 All of the allele frequencies p2 + 2pq + q2 =1 All of the
genotype frequencies together equals 1
p2 and q2 Frequencies for each homozygotes 2pq
Frequencies for Heterozygotes.
p2 + 2pq= + q2
Homozygous Dominant Heterozygous Homozygous
recessive
If the frequencies of the color in Homozygous recessive
frequencies pea plants are 30% in the population what are the
genotype and phenotype frequencies in the populations. A homozygous
recessive plant would be (pp) and a Homozygous dominant...

Will Be Given on Exam: p + q = 1 p = AA + ½Aa q = aa + ½Aa p2 +
2pq + q2 = 1 (p + q)2 = 1 X2 = [(observed - expected)2 /
expected] X2 2, 0.05 = 6.00
1) Blue eyes are a homozygous recessive genotype within humans.
Within the human population, you have 225 individuals with blue
eyes, 480 individuals that are homozygous dominant for brown eyes,
and 125 people that are...

If the frequency of people with sickle-cell anemia in a village
in Africa is 0.0025, and the population is at Hardy-Weinberg
equilibrium, which is closest to the frequency of
heterozygous carriers of the sickle-cell
allele?
A) 0
B) 0.0025
C) 0.005
D) 0.025
E) 0.05
F) 0.1
G) 0.2
H) 0.3
I) 0.4
J) 0.45
K) 0.5
L) 0.6
M) 0.7
N) 0.8
O) 0.9
P) 0.95
Q) 0.975
R) 0.9975
S) 1

1. The formula for
Hardy -Weinberg equilibrium is normally written as:
A.
p2 + 2pq +
q2 = 1
B.
p2 +
q2 = 1
C.
p = qr2
E = (RT/zF) * ln (p/q)
Question 2
Genetic drift is:
a.
Change in the allele
frequencies of a population over time due to random effects
b.
Change in the genetic
composition of an individual due to random mutations
c.
Change in the allele
frequencies of a population over time...

) Imagine that you are a grad student in
Biological Anthropology, and you travel to the land of
“Jenesaiquoivia” to study Jenesaiquoivian genetics. [Footnote
1]
You notice that 9 out of every 100 people in your study group have
blue eyes. The rest of the population have brown eyes. You know
that the brown eyes allele is dominant, and blue eyes is recessive.
[2]
Construct the Hardy-Weinberg equation for that population. You
know that q2=.09 (9%) so p2 plus 2pq...

18.If population 1 is in Hardy-Weinberg equilibrium such that p
= 0.7, and q = 0.3, select all of the following that would result
if mating began to occur with the adjacent population 2 in which p
= 0.1 and q = 0.9. Select ALL that
apply.
Group of answer choices
A) Population 1 will shift out of Hardy-Weinberg equilibrium
B) Population 2 will stay in Hardy-Weinberg
C) In population 2, p will increase
D) In population 1, p will increase...

Part I. You are investigating the evolution of
cuticle color in a scarab beetle inhabiting a desert. Coloration is
determined by a single gene A with two alleles:
A1 codes for a dark brown
color, and A2 codes for a grey
color. Since the alleles are incompletely dominant,
heterozygotes are tan. Therefore
the heterozygotes are almost invisible on the sandy desert floor,
while homozygotes are more visible and thus more susceptible to
predation.
Questions: (a) Based on the given information,...

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