Question

1. The mature mRNA molecule for the EDS1 transcript is 1903 nucleotides long, starting with an...

1. The mature mRNA molecule for the EDS1 transcript is 1903 nucleotides long, starting with an initiation codon at one end and a termination codon at the other end. The number of amino acids in the protein translated from this mRNA is:

2. You’ve just determined the first four amino acids in the amino-terminal end of a the EDS1L Arabidopsis protein. The peptide sequence is: (NH4)- met-ala- phe-glu- (COOH). What is the nucleotide sequence in the portion of the mRNA encoding this protein?

Homework Answers

Answer #1

Given that a mature mRNA molecule of EDS1 transcript is 1903 nucleotides.
There is one initiation codon = methionine= 1 amino acid
There is one termination codon= 1903-3= 1900
So there are 1900 nucleotides and each amino acid constitutes 3 nucleotides.
So number of amino acids formed is = 1900/3= 633.3
I think there is a problem with number of nucloetides.
The nucleotides should be either 1902 or 1905, then aminoacids translated would be either 634 or 635.

2.
The peptide sequence is: (NH4)- met-ala- phe-glu- (COOH)
Nucleotide sequence is: auggcguuugaa (most likely because amino acids codons are redundant)

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