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What is the free energy change for the transport of calcium ions into a cell. The...

What is the free energy change for the transport of calcium ions into a cell. The intracellular [Ca2+] is 1 μM and extracellular [Ca2+] is 1 mM. Assume a membrane potential of -100 mV and T=25°C. Give your answer in kJ/mol to one decimal place.

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Answer #1

Delta Gin= RT ln ([Ca2+]in/[Ca2+]out])+ ZFVm

Z= +2 for calcium

F= Faradays constant= 23062cal/ mol-1

R= 1.986 calories/mol-K=2                

T= 273+ 25= 298.15K

Delta Gin= 2 * 298 * ln 0.001/1 + 2* 23062* (-100/1000 V)

                 = 2 * 298 * (-6.9077) + 2* 23062 * (-0.1)

               = - 4116.9-4612.4 = 8729.3 calories/mol= -8.7 kcal/mol= -8.7 * 4.184= -36.4 KJ/mol

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