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In a certain population, 4% of the population is born with sickle cell anemia (aa). Calculate...

In a certain population, 4% of the population is born with sickle cell anemia (aa). Calculate the percentage of individuals who enjoy the selective advantage of the sickle-cell gene( increased resistance to malaria)?

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Answer #1

Individuals who are carrier of sickle cell anemia (A a) enjoy the selective advantage of the sickle-cell gene (increased resistance against malaria)

HARDY-WEINBERG EQUILIBRIUM:

p + q = 1

p2 + 2pq + q2 = 1

Where,

p and q = frequency of the dominant and recessive allele respectively in the population.

Also,
p2 = percentage of AA (homozygous dominant) individuals
q2 = percentage of aa (homozygous recessive) individuals
2pq = percentage of Aa (heterozygous individuals)

given,  q2 = 4% = 0.04

q = 0.2

p = 1 - 0.2 = 0.8

Now, 2pq = 2*(0.2)*(0.8) = 0.32 (required answer)

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