Question

1. The lac operon responds to lactose and glucose. If wild-type E. coli cells are grown...

1. The lac operon responds to lactose and glucose. If wild-type E. coli cells are grown in media that contains both lactose and glucose, they will consume the glucose first because: (select all that apply)

A.) the lac repressor remains bound to lacO, preventing the lac operon from being expressed at maximal levels
B.) the permease (lacY) is not expressed in the presence of glucose, preventing lactose from entering the cell and being converted to allolactose, the inducer
C.) the CAP protein cannot bind the CAP binding site, preventing the lac operon from being expressed at maximal levels
D.) the lac promoter is weak, so even though lac repressor is not bound to lacO, there is far less than maximal expression of the lac operon

2.) The small molecule that regulates CAP's ability to bind DNA: (select all that apply)

A.) is glucose
B.) is an isomer of glucose
C.) is present at high levels in the presence of glucose
D.) is present at low levels in the presence of glucose

3.) The lac operon is regulated by BOTH a repressor AND an activator because: (select all that apply)

A.) the repressor responds to one environmental condition and the activator responds to a completely different environmental condition.
B.) the lac operon is an AND gate, and AND gates need to have a repressor and an activator
C.) the lac operon is an AND gate: it is only maximal when there is lactose AND no glucose
D.) operons always need one repressor and one activator or they would never be completely ON (maximal) or completely OFF (basal).

4.) The following mutation(s) would cause the lac operon to be expressed at less than maximal levels in the presence of lactose & absence of glucose: (select all that apply)

A.) a mutation in CAP that prevents it from binding cAMP
B.) a mutation in CAP that locks it in the DNA-binding conformation, independent of whether cAMP is present or not.
C.) a mutation in CAP that prevents it from dimerizing.
D.) a deletion of the adenylate cyclase gene

Homework Answers

Answer #1

Repressor is bound at lac o and prevent lac operon to express.

Cap protein is unable to bind at caps site due to lower level of cmp hence option A and C are correct

2. CAP is present in lower level binded with cAMP in higher concentration of glucose hence option C is right.

3. Operon always need a repressor or activate a protein to express operon and they are never complete not on or off hence option D is right.

4. Mutation which remain always CAP binded at cap site will result in highr expresson of operon so option B is correct.

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