Question

In one of my labs, we had a sucrose/water mixture with varying amounts of each tube. The total volume that contained water and sucrose was 12.5 mL. There was 15 uL of 100g/L sucrose and 1235 uL of water in the first tube. The molecular weight for sucrose is 342.30 g/mol. How do I calculate the absolute amount of substrate (sucrose) in uM concentration? Please show the steps. Thanks!

Answer 1

The total volume that contained water and sucrose was 12.5 mL.
There was 15 uL of 100g/L sucrose and 1235 uL of water in the first tube.
Using unitary method, 15 uL of 100g/L sucrose contains (100g / 1000000 uL) * 15 uL = 0.0015 grams
The molecular weight for sucrose is 342.30 g/mol.
Using unitary method, 0.0015 grams would constitute, (1/342.30) *0.0015 = 4.38 uM absolute amount of sucrose

How do I calculate the absolute amount of substrate (sucrose) in uM concentration? Please show the steps. Thanks!