Question

It’s demanding to measure the standard free-energy change associated with the hydrolysis of ATP because the...

It’s demanding to measure the standard free-energy change associated with the hydrolysis of ATP because the minute amount of ATP remaining at equilibrium is difficult to measure accurately. The value of ΔG'º can be calculated indirectly, however, from the equilibrium constants of two other reactions (the first of which should look familiar) that have less favorable equilibrium constants:

glucose-6-phosphate + H2O à glucose + Pi                    Keq'=270

ATP + glucose à ADP + glucose-6-phosphate   Keq'=890

Using this information, calculate ΔG'º for hydrolysis of ATP in units of kcal/mol.

Show all your work.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Standard Free Energy of Hydrolysis, ∆ G o', of some organophosphate compounds (phosphate isreleased as one...
Standard Free Energy of Hydrolysis, ∆ G o', of some organophosphate compounds (phosphate isreleased as one of the products of hydrolysis)                                     Compound kJ/mol phosphoenolpyruvate -61.9 carbamyl phosphate -51.4 creatine phosphate -43.1 acetyl phosphate -42.2 ATP (to ADP) -30.5 Glucose-1-phosphate -20.9 Glucose-6-phosphate -13.8 Glycerol-3-phosphate -9.2 Use the table in the above table to calculate the ∆G o' (in kJ/mol) for the following reaction: ATP +  glucose --------> ADP  +  glucose-6-phosphate
The standard Gibbs free energy change for hydrolysis or pure ATP to pure ADP is -31KJ/mol....
The standard Gibbs free energy change for hydrolysis or pure ATP to pure ADP is -31KJ/mol. The reaction is written ATP = ADP +Pi. What is the Gibbs energy of reaction in an environment at 37 C in which the ATP, ADP, and Pi concentrations are all 1mmol/L or 1 µmol/L?
The standard free energy change for ATP hydrolysis is -30.5 kJ/mol. Therefore, the free energy change...
The standard free energy change for ATP hydrolysis is -30.5 kJ/mol. Therefore, the free energy change for this reaction in a cell in which the concentration of ATP, ADP, and Pi are 3.1 mM, 2.2 mM and 6.8 mM, respectively, and assuming a physiologically relevant temperature (37 °C), is: Answer -44.25 kJ/mol explain
Many metabolic reactions are coupled reaction. Such as the first step in glycolysis drawn below: Glucose...
Many metabolic reactions are coupled reaction. Such as the first step in glycolysis drawn below: Glucose + Pi ↔ glucose-6-phosphate + H2O a. The ΔG°’ is 14 kJ•mol-1. What is the ratio of [G6P]/[glucose][Pi] at equilibrium at 25°C? b. The above reaction is coupled to the hydrolysis of ATP. In muscle cells at 37°C, the steady-state ratio of [ATP]/[ADP] is 12 & the ΔG°’ for ATP hydrolysis is -30.5 kJ•mol-1. Assuming that glucose and G6P achieve equilibrium values in muscle...
The glucose/glucose-6-phosphate substrate cycle involves distinct reactions of glycolysis and gluconeogenesis that interconvert these two metabolites....
The glucose/glucose-6-phosphate substrate cycle involves distinct reactions of glycolysis and gluconeogenesis that interconvert these two metabolites. Assume that under physiological conditions, [ATP]=[ADP] and [Pi]=1mM. Consider the following glycolytic reaction catalyzed by hexokinase: ATP+glucose⇌ADP+glucose−6−phosphateΔG∘′=−16.7kJ/mol Calculate the equilibrium constant (K) for this reaction at 298 K, From the equilibrium constant, calculate the maximum [glucose-6-phosphate]/[glucose] ratio that would exist under conditions where the reaction is still thermodynamically favorable. The reverse of this interconversion in gluconeogenesis is catalyzed by glucose-6-phosphatase: glucose−6−phosphate+H2O⇌glucose+PiΔG∘′=−13.8kJ/mol K= 262 for...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT