Question

I need to prepare a 10 mL 3.0 mM hydrogen peroxide solution from a bottle of 3% Hydrogen peroxide. What are the calculations necessary to figure out how to prepare the solution and what is the ratio to be used in order to create apoptosis in saccharomyces cerevisiae yeast cells.

Answer 1

We know that Molecular weight (MW) of H₂O₂ is 34.01 g/mol

3% H₂O₂ needs to be Diluted to 3 mM or 0.003 M (a molarity is one mole of substances in 1000 mL of solution)

Therefore, Mole = Weight (g)/ MW

and, Mole = Conc (M) X Volume (L)

Then substituting above two equation,

Weight/MW = Conc X Volume

Weight/ Volume = conc X MW = 0.003 M X34.01 g/mole = 0.10203 g/L of H₂O₂. ----------C₂

Now, 3% of H2O2 = 3g/100ml of H₂O₂ = 30g/1L of H₂O₂ -------------- C₁

V₂ = final volume of diluted or need volume = 10 ml

V₁ = Volume need to be taken from stock

Material balance equation,

V₁ C₁ = V₂ C₂

V₁ = 0.10203 X 10/30

V₁ = 0.03401 ml of 3% H₂O₂ in 10 ml of H₂O