A pet shop is breeding neon tetra fish and find some interesting color phenotypes. 1. The breeder crosses a true-breeding red neon tetra to a true-breeding yellow neon tetra and finds that all F1 progeny are red. Crossing two F1 red neon tetras results in the following numbers of progeny: 36 Red neon tetras, 3 Yellow neon tetras, and 9 Orange neon tetras. How many genes are involved in neon tetra coloration? |
|||||||||||||||||||
a. 1 b. 2 c. 3 d. 4 e. Cannot be determined from the information given
|
1.
Red = Dominant = R_N_ or rr N_
Yellow = Recessive = rrnn
Orange = R_nn
Parental cross: RRNN X rrnn
F1 Progeny = RrNn = All red
F1 selfing: RrNn X RrNn
Phenotypic ratio = 36 red : 3 yellow : 9 orange
Phenotypic ratio = 12 red (R_N_ or rr N_) : 1 yellow (rrnn) : 3 orange (R_nn)
This is dominant epistasis ratio. A dominant allele at one locus is sufficent to mask the effect of recessive alleles at the other locus.
Number of genes involved = 2 (Four alleles)
Red neon tetra genotype = A_B_ and aaB_
So, option F is correct.
Get Answers For Free
Most questions answered within 1 hours.