Question

9.The allele for freckles is dominant to the allele for no freckles. A freckled man and...

9.The allele for freckles is dominant to the allele for no freckles. A freckled man and a woman without freckles have two children, a boy with freckles and a girl without freckles. Using a Punnett square, determine the genotypes of all four individuals.

Mom: X^f X^f

Dad: X^f Y

Homework Answers

Answer #1

Genotypes of 4 individuals in the family are

Father - Ff

Mother - ff

Boy - Ff

Girl - ff

Punnet square -


Explanation
Allele for freckles - F (dominant)

Allele for no freckles - f (recessive)

**One of the parents has freckles and one do not.

One with freckles can be of genotype FF or Ff

One without freckles must be ff

**One of the children has freckles(boy) and one do not(girl).

Boy can be of genotype Ff or ff

Girl has a genotype ff

** As one child is having ff genotype , both f alleles should come from each parents.

So genotype of freckled man must be Ff

**As one parent is of genotype ff, genotype of freckled boy can never be FF . He has genotype Ff

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In humans, albinism is controlled by a single recessive allele ( c ), and normal skin...
In humans, albinism is controlled by a single recessive allele ( c ), and normal skin pigmentation is controlled by the dominant allele ( C ). A) If a homozygous normal male marries a woman with albinism, what are their chances they will have a baby with albinism? Show the Punnett Square for your answer. B) If a heterozygous normal female marries a man with albinism, what are their chances they will have a baby with albinism? Show the Punnett...
Freckles are dominant to no freckles. Two people who have freckles and are heterozygous marry. What...
Freckles are dominant to no freckles. Two people who have freckles and are heterozygous marry. What are the genotypes and phenotypes of all the offspring? Use F and f.
A widow’s peak is an autosomal dominant trait while a straight hairline is a recessive trait....
A widow’s peak is an autosomal dominant trait while a straight hairline is a recessive trait. Mike and his dad have a widow’s peak. Mike marries Bethany who has a continuous hairline like Mike’s mom. What is the probability that Mike and Bethany’s first child will have a widow’s peak? Complete Punnett Square to support your answer. Leave Blank Probability of first child: A 15-year old boy was diagnosed with a usual autosomal inherited form of diabetes. His mother was...
1) The allele for free-hanging earlobes (E) is completely dominant over the allele for attached earlobes...
1) The allele for free-hanging earlobes (E) is completely dominant over the allele for attached earlobes (e). A man with attached earlobes marries a woman with free-hanging earlobes. All of their children have free-hanging earlobes. What is the woman's genotype? 2)The allele for free-hanging earlobes (E) is completely dominant over the allele for attached earlobes (e). A man with attached earlobes marries a woman with free-hanging earlobes. All of their children have free-hanging earlobes. What is the genotypic ratio of...
An autosomal dominant condition causes deafness in people. However, 40% of people who are known to...
An autosomal dominant condition causes deafness in people. However, 40% of people who are known to have at least one copy of the dominant allele have normal hearing (no deafness). Additionally, the severity of deafness varies between individuals with the condition. Some people have complete deafness, some people moderate deafness, and some people only have mild deafness. The occurrence or not of deafness in people who have at least one dominant allele is an example of: Codominance Epistasis Expressivity Penetrance...
In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele...
In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled.             a. What is the genotype of the woman's father?             b. What is the probability that the couple's first child will be a non-freckled,...
1) A woman with blood type A marries a man with blood type B. Their three...
1) A woman with blood type A marries a man with blood type B. Their three children have blood types A, AB, and B. Which trait, if any, is dominant? Explain. What are the genotypes of the parents? What is the probability of these parents having a child with blood type O? Show your Punnett square.
Duchenne muscular dystrophy, or DMD, is the result of a recessive allele. If a woman with...
Duchenne muscular dystrophy, or DMD, is the result of a recessive allele. If a woman with DMD and a man without DMD have children, all of the sons will have DMD, but none of the daughters will. Why does this occur? DMD is sex-linked, and all daughters will inherit a dominant allele from their father. DMD is sex-linked, and all sons will receive a recessive allele from their father. Multiple alleles control the expression of DMD in daughters, who have...
Having freckles is a dominant trait. A person is heterozygous for having freckles. Their genotype is...
Having freckles is a dominant trait. A person is heterozygous for having freckles. Their genotype is _________ and their phenotype is _________. [ Choose the choice with the answers in the correct order. ] * Freckles, Ff ff, freckles freckles, no freckles Ff, Freckles A fertilized egg created through sexual reproduction ______________. * is genetically identical to the parents contains genetic material from only one parent is genetically identical to other eggs of the same parents has a combination of...
A man with hemophilia (a recessive, sex-linked condition) and a woman that carries the hemophilia allele...
A man with hemophilia (a recessive, sex-linked condition) and a woman that carries the hemophilia allele have a daughter with normal phenotype. Define allele symbols for the hemophilia and normal alleles. Draw a pedigree and indicate the genotype of each individual in the pedigree. The daughter marries a man who is normal for the trait. What is the probability that a daughter of this pair will be a hemophiliac? What is the probability that a son will be a hemophiliac?...