. After cloning the Citrate Synthase gene you consulted the genome databases and find that the human Citrate Synthase enzyme (found in the Krebs Cycle) primary conformation begins with the amino acid sequence Met-Trp-Lys-Trp- Trp-Met. But the protein made from your plasmid begins with Met-Trp-Met-Trp-Trp-Met! A mutation must have occurred! Write out the most likelyDNA sequence of the non-templated strand for the beginning of the actual (unmutated) Citrate Synthase gene. Don’t forget 5′ and 3′ ends.
As the question says sequence of the non template strand, first lets see what is the template and the non template strand , template strand is the strand of the DNA which is transcribed into the RNA.
now first lets write the RNA sequence for this given aminoacid sequence Met-Trp-Lys-Trp-Trp-Met for this the RNA sequence would be 5'AUGUGGAAAUGGUGGAUG3'
Now this is the RNA sequence from the template strand. now from this sequence the DNA sequence will be
3'TACACCTTTACCACCTAC5' from this the non template strand sequence will be
5ÁTGTGGAAATGGTGGATG3' this the nontemplated DNA strand sequence for unmutated enzyme.
Get Answers For Free
Most questions answered within 1 hours.