Question

A population has the following data: Genotype Number AA 65 Aa 5 aa 25 Calculate the...

A population has the following data:

Genotype Number

AA 65

Aa 5

aa 25

Calculate the allelic frequency for the a allele.

Science   Biology   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

total population = 95

total alleles = 190

allelic frequency of a = 1×5 + 2×25 /190

                                 =55/190

                                  =0.289

allelic frequency % = 28.9 (a)

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. Consider a population where the following numbers of individuals have the indicated genotype: 32 AA,...
1. Consider a population where the following numbers of individuals have the indicated genotype: 32 AA, 56 Aa, 12 aa. This population shows… a. positive assortative mating, b. negative assortative mating, c. cannot determine, d. random mating 2. Consider a population where the following numbers of individuals have the indicated genotype: 36 AA, 48 Aa, 16 aa. This population shows… a. positive assortative mating, b. negative assortative mating, c. cannot determine, d. random mating
Genetic Makeup of a Mouse Population Genotype Phenotype Number of Individuals in Original Population Number of...
Genetic Makeup of a Mouse Population Genotype Phenotype Number of Individuals in Original Population Number of Individuals in New Population BB Brown 841 841 Bb Tan 1218 1218 bb Gray 441 0 Total 2500 2059 The genetic makeup of a mouse population is provided in the table above. At the start of an experiment, researchers remove all the gray mice from the population, resulting in a population that is not in Hardy-Weinberg equilibrium. Calculate the frequency of the recessive allele...
You observe that in a population of humans that the ADH locus has the following genotype...
You observe that in a population of humans that the ADH locus has the following genotype counts: AA = 300, Aa = 500, and aa = 200. What are the expected Hardy-Weinberg genotype frequencies for this locus in this population? A. 0.3025 (AA), 0.495 (Aa), 0.2025 (aa) B. 0.2500 (AA), 0.500 (Aa), 0.2500 (aa) C. 0.5500 (A), 0.4500 (a) D. 1.000 (AA), 0.000 (Aa), 0.000 (aa) E. 0.333 (AA), 0.333 (Aa), 0.334 (aa)
Please Show Work!! Calculate the number of individuals with a dominant phenotype (assuming dominance of allele...
Please Show Work!! Calculate the number of individuals with a dominant phenotype (assuming dominance of allele A over allele a) considering the following: the population is in Hardy-Weinberg equilibrium, it has 100 individuals, and the frequency of the homozygote recessive genotype is 0.2. (round to the nearest integer).
A population of cats has 120 black individuals (BB genotype), 45 brown individuals (Bb) and 25...
A population of cats has 120 black individuals (BB genotype), 45 brown individuals (Bb) and 25 light brown individuals (bb). Use the method of counting the number of alleles to determine the gene frequency
a population consists of 1000individuals with the following genotypes: AA 350 Aa 525 aa 125 what...
a population consists of 1000individuals with the following genotypes: AA 350 Aa 525 aa 125 what is the frequency of A? frequency of a? genotypic frequency of this population? show calculations.
Consider a racoon population that exhibits variation at the G locus, which has two possible alleles:...
Consider a racoon population that exhibits variation at the G locus, which has two possible alleles: G1 and G2. The population starts out at Hardy Weinberg Equilibrium and the frequency of the G1 allele in the original population is 0.3. The relative fitness of each genotype during this generation is listed below. Use information to answer the following questions. w11 = 0.8 w12 = 1.0 w22 = 0.5 Calculate the average fitness for the population. Calculate the genotype frequencies in...
Will Be Given on Exam: p + q = 1 p = AA + ½Aa q...
Will Be Given on Exam: p + q = 1 p = AA + ½Aa q = aa + ½Aa p2 + 2pq + q2 = 1 (p + q)2 = 1 X2 =  [(observed - expected)2 / expected] X2 2, 0.05 = 6.00 1) Blue eyes are a homozygous recessive genotype within humans. Within the human population, you have 225 individuals with blue eyes, 480 individuals that are homozygous dominant for brown eyes, and 125 people that are...
A gene in a randomly-mating population has two alleles (A,a), and the allele frequency of A...
A gene in a randomly-mating population has two alleles (A,a), and the allele frequency of A is 0.65. Calculate the frequency of homozygous recessive individuals (aa) in the population.
The frequency of a dominant allele A in a population is P = 0.4, and the...
The frequency of a dominant allele A in a population is P = 0.4, and the rate of a recessive allele a at the same locus is q = 0.6. Assuming that allele a is fatal in double dose (individuals with genotype aa die in the fetus). a) What happens with the frequencey to the a-allel in the long term? b) Why will a never completely be gone if the population has infinite size?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT