Question

II. Use the DNA sequence below, which encodes a eukaryotic gene to answer the following questions. 1 11 21 31 41 GGCGTATAAA GCGACGACTG TAGACTGATG AGCCTATCCA TGGACGCGCC 51 61 71 81 91 ATGGCCCTGT AAGCGGTGCG ATGCAATAAA ACGCGTATCA GTCATTCAGC 101 111 121

  GTAGTCTGAT GCCAGTCGAC TGC

a) Write down the corresponding sequences, find them in the sequence above and label them: TATA box sequence: _________________ (label as TATA)
Polyadenylation signal in corresponding mRNA: ____________ (label as Poly-A) Kozak’ssequenceincorrespondingmRNA:________________ (labelasKozak)

Start (initiation) codon in corresponding mRNA: _______ (label as start) Stop(termination)codonincorrespondingmRNA:_______ (labelasstop)

b) What region of the mRNA contains the open reading frame that will be translated into protein?

41-101 27-35 51-59 71-77

c) Where is the 3’UTR? Circle one.
59-101 51-123 63-101 71-81

Answer 1

TATA: starts in base number 5 and ends in number 10 (TATAAA)

Poly-A: starts in number 75 and ends in 80 (AATAAA)

Kosak: starts in base number 48 and ends in 54 (GCCATGG). the start codon is AUG and in the DNA woulb be ATG. The Kosak sequence surrounds this codon as ACCATGG (or similar). We also know this is the sequencue because there is only one possible stop codon (TAA) that matches the reading frame 3 by 3 starting on this ATG

Start: base number 51-53 (ATG)

Stop: 60-62. there are three possible stop codons: TAG, TGA and TAA, in this case is TAA.

The translation starts at AUG (translated to metionin) and ends just before the stop codon, so it is 51-59.

c) the 3' UTR region starts exactly after the stop codon, so the region is 63-101.