Question

Calculate the daily fluoride intake of a dairy animal from (a) air and (b) food and water, based on the conditions below and assuming 100% retention of the fluoride:

– Animal breathing rate: 30 kg air per day containing 6 μg fluoride per cubic meter of air (STP).

– Animal food and water intake:

Herbage 10 kg containing 200 mg kg1 of fluoride.

Water 5 kg containing 1 mg kg1 of fluoride

Answer 1

Animal breathing rate 30 kg air per day

1 cubic meter of air = 1.293kg

30 kg of air= 30/1.293 cubic meter

= 23.202 cubic meter

Amount of fluoride in 1 cubic meter of air= 6uG

Amount of fluoride in 30kg of air= 6/23.202

= 139.211ug

= 0.139211mg ( 1000ug=1mg)

Amount of food intake= 10kg

Amount of fluoride in 10 kg food= 200 x 10

=2000mg

amount of water intake = 5 kg

Amount of fluoride in 5kg of water= 1 x 5

=5mg

Total daily gluoride intake of dairy animal = 0.139211 + 2000 + 5

=2005.1392 mg