Question

In a population of 70 storm petrels, you measure 80 AB chromosome and 32 Ab chromosomes. If the two loci are in linkage equilibrium, how many ab and aB chromosomes would you expect to see?

A. 8 ab chromosomes and 20 aB chromosomes

B. 20 ab chromosomes and 8 aB chromosomes

C. 32 ab chromosomes and 80 aB chromosomes

D.80 ab chromosomes and 32 aB chromosome

E. 14 ab chromosomes and 14 aB chromosomes.

Answer 1

Answer: 80 ab chromosomes and 32 aB chromosome

Explanation: As given, we can see that 'AB' and 'ab' are the parental combination here and 'Ab' and 'aB' are the new combinations. As the genes are in linkage, hence we will found more parental combination than the new combinations. As 80 AB chromosomes are here, we will find 80 ab chromosomes. Also, as 32 Ab chromosomes are here, we will found 32 aB chromosomes.

When Morgan has crossed, he has found 41.5 % of individuals for both dominant and recessive parental combination (PC) and 8.5% of people belonging to new combinations (NC).

Hence, as a total he has found 41.5% PC +41.5% PC + 8.5 % NC + 8.5% NC = 100%