According to Mendel's law of independent assortment, an organism with genotype AaBb, will produce what combination of gametes?
Group of answer choices
Gametes with genotypes A, a, B, and b in roughly equal numbers
Gametes with genotypes AB and ab in roughly equal numbers
Gametes with genotypes AB, Ab, aB, and ab in roughly equal numbers
Gametes with genotypes Ab and aB in roughly equal numbers
According to Mendel's law of independent assortment, an organism with genotype AaBb, will produce what combination of gametes?
Gametes with genotypes AB, Ab, aB, and ab in roughly equal numbers
Explanation- The law of independent assortment states that when cross is made between two individuals different from each other in two or more characters, the inheritance of one character is independent of the inheritance of another character. Besides the parental types, recombinants are also obtained.
Types of gametes= 2n, where n is the number of hybrid traits.
Genotype of organism is AaBb, so it heterozygous for 2 loci
Therefore, n=2
So 22= 4
i.e., 4 types of gametes (AB, Ab, aB, ab)
Ps- An upvote would be highly appreciated
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