Question

Scanning (40X): 1.8 mm x (100X/40X) =______ mm =_________ μm

- Low power (100X): FOV diameter = 1.8 mm =__________ μm

- High power (400X): 1.8 mm x (100X/400X) =__________ mm =__________ μm

- Oil immersion (1000X): 1.8 mm x (100X/1000X) =___________ mm =____________ μm

Answer 1

The field of view (FOV) is the actual “circle” you see when looking in the microscope. The diameter of the field of view (FOV diameter) at a particular magnification gives the size of the specimen you are viewing. The FOV diameter at low power for your microscope (100X) is ~1.8 mm. Using this FOV diameter, you can calculate the FOV diameter at other magnifications. This is done by the following formula

Unknown FOV= known FOV diameter x total mag. (known FOV) / diameter total mag. (unknown FOV)

Scanning (40X): 1.8 mm x (100X/40X) = 1.8 mm = 1800 μm

- Low power (100X): FOV diameter = 1.8 mm = 1800 μm

- High power (400X): 1.8 mm x (100X/400X) =0.45 mm = 450 μm

1.8 mm x (100X/400X) = 1.8mm x ¼ = 1.8mm x 0.25 = 0.45 mm = 450 μm

- Oil immersion (1000X): 1.8 mm x (100X/1000X) = 0.18 mm = 180 μm

1.8 mm x (100X/1000X) = 1.8 x 1/10 = 1.8 x 0.1 = 0.18 mm = 180 μm