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Gene A (alleles A & a) is 21 map units from Gene B (alleles B &...

Gene A (alleles A & a) is 21 map units from Gene B (alleles B & b) and, on another chromosome, Gene C (alleles C & c) is 12 map units from Gene D (alleles D & d). Which of the gene pairs (A & B or C & D) would you expect to have more recombinant offspring after a test cross? Why?

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Answer #1

The distance between two genes on a chromosome decides the probability of their recombination. If the genes are present far away from each other, then there are high chances of their separation through crossing over than those which are present close to each other. If they are getting separated through crossing over, they will produce recombinants.

In the question, the distance between Gene A and B is 21 map units and between C and D is 12 map units. So the distance between A and B is greater, which means that Gene pair A and B have more chances of separation through crossing over and thus will be having more recombinant offsprings after a test cross.

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