What is the pH of human urine if proton concentration is 6.3 x 10^-7 M?
Please show all work and explain your responses.
pH can be defined as the negative logarithm of proton concentration in a medium. The formula for pH is given as :
pH = - log10 [H+]
In the above question, the proton concentration of urine is given as 6.3 x 10^-7 M. So we calculate pH using the above formula :
pH = - log10 [H+]
= - log10[ 6.3 x 10-7]
= - log10 6.3 + - log10 10-7
= - 0.799 + 7 log10 10
= - 0.799 + 7
= 6.201 or 6.2
Thus the pH of urine at a proton concentration of 6.3 x 10^-7 M is 6.2. A pH value below 7 is considered as acidic. Thus the urine is acidic in nature.
PS - The log value of log10 6.3 was calculated using log table. We know that the value of log10 10 = 1.
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