Question

Consider an initial population of 512 AA individuals 320 Aa individuals , and 115 aa individuals aWhat are the frequencies of the alleles ?

Answer 1

Answer- genotype frequencies-

Total population is 512+320+115 = 947

To calculate frequency of AA= no of AA / total population

So 512 / 947 = 0.54

Frequency of aa = 115/947 = 0.12

Frequency of Aa = 320/947 = 0.33.

To calculate allele frequency f( A) = (AA÷ 1/2 Aa)÷ 947.

So 0.54 + 0.165 = 0.705

f(a) =( aa ÷ 1/2 Aa )÷ 947 = 0.121 + 0.165 = 0.286.

Another method is to subtract from 1 as all sum of frequencies is always one.

So 1- 0.705= 0.295 which is frequency of A.

The variation in both answers is because the total sum is 947 and not 1000. When 1 is taken its assumed the population is 1000.

The sum of allele frequencies is always less than one or should be 1.the allele frequencies would add upto 1 if the total population was 1000 .

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