Question

In the following cross, AaBbCcDd x AaBbCcDd what is the probability of producing a child that will have the same phenotype as the parents? Assume complete dominance.

Answer 1

AaBbCcDd x AaBbCcDd

lets divide it into 4 crosses

	A	a
A	AA	Aa
a	Aa	aa

	B	b
B	BB	Bb
b	Bb	bb

	C	c
C	CC	Cc
c	Cc	cc

	D	d
D	DD	Dd
d	Dd	dd

probability of AaBbCcDd is thus probability of Aa X Bb X Cc X Dd

                                                                         =1/2 X 1/2 X 1/2 X 1/2 =1/16