Question

A DNA template has the following sequence:

5’-GCTTACTGGCCCGGTTTATTGCCCATCGCC-3’

Infer a transcribed mRNA sequence first, identify the start codon, and determine the complete amino acid sequence that would be translated. Be specific about the amino-terminus and carboxyl-terminus.

Answer 1

As rna polymerase transcibes the template strand in from 3 ' to 5 ' so the mRNA will be as follows

5'-GGCG AUG GGC AAU AAA CCG GGC CAG UAA GC-3'

This will be the mRNA sequence .

However it will be in continuation but here for translation purpose we have spkitted it in codons. As AUG is the start codon so translation will be started from here and UAA is the stop codon so it will stop at it and the final aminoacid sequence will be as follows

Amino terminus-Methionine glycine aspartate lysine proline glycine glutamine-carboxyl terminus