a) stock concentration(M1)= 40 mg/mL
final concentration required (M2)= 4 mg/mL
final volume(V2)=50 uL
volume of stock requred (V1)= ?
M1V1=M2V2
V1=M2V2/M1
= (450)/40
= 5 uL
take 5 uL of the stock solution and add 45 uL of 2X sample buffer to it to make the final concentration=4 mg/mL
b) amount of protein required= 20 ug
concentration of the protein= 4 mg/mL
1 mg= 1000 ug
1 mL= 1000 uL
so 1 mg/mL= 1 ug/uL
so 4 mg/mL= 4 ug/uL
concentration of the protein= 4 ug/uL
In 1 uL there is 4 ug of protein, we need 20 ug, so volume of the solution required= amount of protein required/concentration of protein= 20 ug/4 ug/uL=5 uL
volume of the diluted sample to be taken= 5 uL
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