Question

Suppose in pumpkins there are five genes that work additively to affect pumpkin size. A homozygous lower case allele pumpkin, aabbccddee, weighs 20 lbs. Each capitalized allele additively affects the final phenotype by adding one pound from the base pumpkin size. What would the maximum expected size be for pumpkin offspring produced from the cross between a parent with genotype AaBBCcddEE and a parent with genotype AABbccDDEe? Group of answer choices

22 lbs

28 lbs

30 lbs

26 lbs

24 lbs

You are studying a group of Oregonian beavers, and you are interested in the population genetics of a single locus. You genotype 100 beavers and discover that for your locus of interest, there are 55 A¹A¹ homozygotes, 20 A¹A² heterozygotes, and 25 A²A² You estimate that the frequency of the A¹ allele is ["0.65", "0.35", "0.20"]         and that the expected number of A¹A² heterozygotes under Hardy-Weinberg equilibrium should be [ "12.25", "45.5", "50"]

choose number value for both blanks

Answer 1

A pumpkin with maximum weight will have maximum number of dominant alleles.

AaBBCcddEE × AABbccDDEe

Convert this pentahybrid cross into 5 monohybrid crosses.

Aa × AA = Aa, AA

BB × Bb = BB, Bb

Cc × cc = Cc, cc

DD × dd = Dd

EE × Ee = EE, Ee

We will take from each cross genotype with maximum # of dominant alleles.

AABBCcDdEE

Minimum weight of pumpkin = 20 lbs

# dominant alleles in given genotype = 8

Weight contributed by dominant alleles = 8 × 1 = 8 lbs

Final weight = 20 + 8 = 20 lbs

Answer is 28 lbs.

According to the guidelines, only first question answered. Please give a good rating.