Question

Given that the change in enthalpy for the oil in water reaction is practically zero (ΔH = 0) how could we make the reaction go backwards?

		Raise the temperature of the solution
		Lower the temperature of the solution
		Raise the pH of the solution
		Lower the pH of the solution
		None of the above

Adenosine-5'-monophosphate (AMP) can react with inorganic phosphate ion (P_i) in water to form Adenosine-5'-diphosphate (ADP) according to the following chemical equation:

Solution concentrations of AMP, P_i, and ADP were measured at 25°C after the reaction reached equilibrium and found to be 0.241 M, 0.563 M, and 0.132 μM (that is 10^-6M), respectively. Use these observations to answer questions 6-8:

What is the equilibrium constant (K_eq) for the synthesis reaction of ADP from AMP and Pi at 25°C? Give your answer to three significant digits with no units.

Answer 1

The answer is option 5 - none of the above.

Oil is a hydrophobic in nature and are also non polar. Water is a polar molecule and thus oil when poured in water, it does not react with water. It form an emulsion. So as there is no reaction occurs, question of backward reaction is absurd and not possible.

Equilibrium Constant is characteristics of every chemical reaction and is defined as concentration of products divided by concentrations of reactants; each concentration is raised to the power of its coefficient in the balanced chemical equation.

For the reaction between AMP,Pi and ADP all the coefficients are 1.0

AMP+Pi = ADP

Concentration of AMP, Pi and ADP are 0.241 M, 0.563 M, and 0.132 μM

0.132 micromolar = 0.000000132 M

So  K_eq = 0.000000132 / (0.241 X 0.563)

= 0.000000132/ 0.135683

= 0.0000009729