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In a pentahybrid cross (5 genes of interest) two pure bred parents mate (SSTTUUVVWW x ssttuuvvww)...

  1. In a pentahybrid cross (5 genes of interest) two pure bred parents mate (SSTTUUVVWW x ssttuuvvww) to produce an F1 hybrid generation. The F1 progeny are allowed to self-fertilize. What frequency of F2 progeny have the genotype ssTTUuVVWw?

    100

    0

    1/128

    1/64

    1/256
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Answer #1

Crossing the parents: SSTTUUVVWW × ssttuuvvww

Gametes : (STUVW-From one parent),(stuvw-from other parent)

F1 generation:SsTtUuVvWw

Self-fertilization of F1 geleration offspring will give rise to 35= 243 types of genotypes and 25 =32 types of phenotypes.

The number of genotypes equal to 243 which is kept as denominator during representation of the frequency of a particular genotype of the cross.But here in options there is no option having denominator as 243.So, 100 may be the answer which is in first option as zero of second option is not the answer.

To draw the checker board of a pentahybrid cross is very large and not easy to  represent having 243 outputs.

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