Question

Drosohpila Punnet Square of Crosses Make Punnet Squares of the following crosses and explain why the...

Drosohpila Punnet Square of Crosses


Make Punnet Squares of the following crosses and explain why the results are so,

Which allele is heterozygous and which is homozygous , which is dominant and which is recessive

Part A

Drosophila Female Ebony cross Male Vesitgal Wings

Drosophila Male Ebony cross Female Vesitgal Wings

Part B

Drosophila Female Wild Type cross Male Star Eye

Drosophila Male Wild Type cross Female Star Eye


More Information: x- linked inheritance

Science   Biology   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

A) Ebony = W (dominant), Vestigial = vg (Recessive)

Male ( W vg) * Wvg (Female)

gametes= Wvg

Female W (male) vg (male)
W WW Wvg
vg Wvg vgvg

WW= homozygous Dominant ; phenotype =Ebony

Wvg= hetrozygous Dominant ; phenotype =Ebony

vgvg= homozygous recessive ; phenotype =vestigial

Part B

Drosophila Female Wild Type ( XX) cross Male Star Eye (X*Y)

Female X* (male) Y(male)
X XX* XY
X XX* XY

Genotype = Female XX*, Male XY

Phenotype = all normal

Part B

Drosophila Male Wild Type (XY) cross Female Star Eye (X*X*)

Female X* (male) Y(male)
X* X*X* X*Y
X* X*X* X*Y

phenotype = all star eye

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A researcher is interested in a novel gene in drosophila called “COVID” which causes the flies...
A researcher is interested in a novel gene in drosophila called “COVID” which causes the flies to become antisocial and maintain a large distance from other flies. She performs two “reciprocal crosses” to determine the possible genetics of this gene. First, she crosses a true-breeding COVID female to a true-breeding wild-type male and produces the following progeny: All of the female progeny are wild-type and all of the male progeny from this cross are COVID. Next, she does a reciprocal...
The sepia (se) eye mutation is a non-lethal recessive mutation located on chromosome III in Drosophila...
The sepia (se) eye mutation is a non-lethal recessive mutation located on chromosome III in Drosophila (it is not sex-linked, the sex chromosome is chromosome I). Predict the results of a monohybrid cross (F2 generation) with the following parents: a homozygous wild- type female fly and a male fly with sepia eyes. Use a se+ for wild type and se for the mutation. What are the Parental genotypes? ________ The F1 genotypes? _______ Draw a Punnett square to determine the...
In Drosophila, cut wings are controlled by a recessive sex-linked allele (ct), and fuzzy body is...
In Drosophila, cut wings are controlled by a recessive sex-linked allele (ct), and fuzzy body is controlled by a recessive autosomal allele ( fy). When a fuzzy female is mated with a cut male, all the members of the F1 generation are wild-type. What are the proportions of F2 phenotypes, by sex?
Cinnabar eyes (ci), curved wings (cw) and smooth abdomen (sa) are all genes linked in the...
Cinnabar eyes (ci), curved wings (cw) and smooth abdomen (sa) are all genes linked in the order given on chromosome II of Drosophila. The three mutant alleles are all recessive to the wild-type alleles (ci+ wild type eyes; cw+ straight wings; sa+ normal abdomen). A female heterozygous for the mutant alleles at each locus is crossed to a homozygous recessive male (ci cw sa/ci cw sa). They have the following progeny: Phenotype                                                                        Number Cinnabar eyes, straight wings, normal abdomen...
A phenotypically wilptype F1 female fruit fly that was heterozygous for genes controlling body color and...
A phenotypically wilptype F1 female fruit fly that was heterozygous for genes controlling body color and wing length was crossed to a homozygous mutant male tester with black body (mutant allele b) and vestigial wings (mutant allele vg). a. Symbolize the genotype of the dihybrid female and tester male using appropriate Drosophila gene symbolism using b+ and vg+ for the wildtype dominant alleles; b and vg for the recessive mutant alleles. b. What is the genotype of the F1 dihybrid...
Wing size in Drosophila results from a pair of X-linked partially dominant alleles. LM produces long...
Wing size in Drosophila results from a pair of X-linked partially dominant alleles. LM produces long wings and Lm produces miniature wings. When both alleles are present in the heterozygous condition, medium-sized wings are produced. A female fly with miniature wings is crossed with a male that has long wings. a). What are the genotypes of the female and male flies described above? What are the genotypes of the gametes that each fly makes? (4 pts) Female genotype:                                                         Female gamete(s):...
A widow’s peak is an autosomal dominant trait while a straight hairline is a recessive trait....
A widow’s peak is an autosomal dominant trait while a straight hairline is a recessive trait. Mike and his dad have a widow’s peak. Mike marries Bethany who has a continuous hairline like Mike’s mom. What is the probability that Mike and Bethany’s first child will have a widow’s peak? Complete Punnett Square to support your answer. Leave Blank Probability of first child: A 15-year old boy was diagnosed with a usual autosomal inherited form of diabetes. His mother was...
You carry out an F2 cross (with a male heterozygote and a female heterozygote) for this...
You carry out an F2 cross (with a male heterozygote and a female heterozygote) for this gene, which we will call “Eyeless” or “e”. You get the following progeny: 2/3 of the drosophila are wild-type phenotype (e+), 1/3 of the drosophila are small eyes phenotype (e). Which of the following genetics best explains your results? Group of answer choices Eyeless is autosomal dominant with a heterozygote advantage. Eyeless is codominant. Eyeless is autosomal recessive with a lethal allele. Eyeless is...
Question text In drosophila (fruit flies): The yellow gene is on the X-chromosome, the gene product...
Question text In drosophila (fruit flies): The yellow gene is on the X-chromosome, the gene product plays a role in body colour. Wild type flies are a light brown/tan in colour, homozygote yellow mutants have a more yellow shaded body colour. We'll use y+ to represent the wild type allele, and y to represent the mutant allele. y+ is dominant to y. The vestigial gene is on chromosome 2. Homozygote vestigial mutants have very short wings, and cannot fly. We'll...
Which of the following correctly describes this cross? Choose all that apply. Now determine the genotypes...
Which of the following correctly describes this cross? Choose all that apply. Now determine the genotypes of the possible gametes and set up a Punnett square for the cross between two double heterozygotes, as you did before in a previous question (no need to attach that Punnett square). From your Punnett square, determine how many individual kernels have the genotypes and phenotypes shown in the table below. Enter your answers as a number (e.g. 7) not a word (e.g. seven)...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT