Consider a cross between an individual heterozygous for hitchhiker’s thumb and homozygous recessive for freckles (Jjrr, normal thumb and no freckles) and an individual homozygous dominant for both traits (JJRR, Normal thumb and freckles). Determine the genotype and phenotype ratios of the offspring. Assume Mendelian inheritance is occurring.
Genotype of heterozygous individual = Jjrr.
Genotype of homozygous dominant individual = JJRR.
Cross between them Jjrr X JJRR
Gametes formed Jr and jr JR and JR.
Next generation
Male/ Female | Jr | jr |
JR | JJRr(Normal thumb and freckles) | JjRr(Normal thumb and freckles) |
JR | JJRr(Normal thumb and freckles) | JjRr(Normal thumb and freckles) |
Genotypic ratio of the offspring = 2:2.
= 2JJRr :2JjRr.
Phenotype ratios of the offspring = 4:0. All are Normal thumb and freckles.
= 4 Normal thumb and freckles : 0 normal thumb and no freckles.
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