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If red hair is recessive to brown hair, and long tails are recessive to short tails, what would be the expected phenotypic ratio for the progeny produced from crossing a squirrel heterozygous for both characteristics with a squirrel heterozygous for hair color with a long tail?
Question 58 options:
9 red-haired, long-tailed : 3 red-haired, short-tailed : 3 brown-haired, long-tailed : 1 brown-haired, short-tailed |
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9 brown-haired, short-tailed : 3 brown-haired, long-tailed : 3 red-haired, short-tailed : 1 red-haired, long-tailed |
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3 brown-haired, short-tailed : 3 brown-haired, long-tailed : 1 red-haired, short-tailed : 1 red-haired, long-tailed |
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3 red-haired, short-tailed : 3 red-haired, long-tailed : 1 brown-haired, short-tailed : 1 brown-haired, long-tailed |
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3 brown-haired, short-tailed : 1 brown-haired, long-tailed : 3 red-haired, short-tailed : 1 red-haired, long-tailed |
Which statement about linkage is INCORRECT?
Question 46 options:
Linked genes are always on the same chromosome |
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Linkage results in less than 50% of progeny having the parental phenotypes. |
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Linkage results in more than 50% of progeny having the parental phenotypes. |
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Linked genes demonstrate less than 50% recombination. |
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Unlinked genes demonstrate 50% recombination. |
The process of translation utilizes energy in the form of ATP.
Question 47 options:
True | |
False |
58. Answer: Option C is correct
Explanation:
Red hair = r
Bown hair = R
Long tail = l
Short tail = L
Parental cross: RrLl X Rrll
Progeny:
RL/Rl = Brown short
Rl/Rl = Brown long
rL/Rl = Brown short
rl/Rl = Brown long
RL/rl = Brown short
Rl/rl = Brown long
rL/rl = Red short
rl/rl = Red long
Brown short = 3
Brown long = 3
Red short = 1
Red long = 1
Phenotypic ratio = 3:3:1:1
46. Answer: Option B is correct
Explanation:
Due to Linkage, parental combinations are over-represented than
recombinants in the progeny.
47. Answer: Option B is correct
Explanation:
The given statement is false.
The process of translation is driven by GTP hydrolysis.
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