you have crossed red flowers to green flowers and seen the following outcome All Brown *assume that red and green are both recessive and that red is epistatic to green. What is the F1 genotype and the expected F2 outcome
The inheritance pattern is recessive epistasis. The traits are controlled by two genes, each gene with two alleles.
A_B_ = Brown
aaB_ or aabb = red
A_bb = Green
aaBB (red) x AAbb (green)----Parents
aaBB genotype produces only one type of gametes with genotype, aB.
AAbb genotype produces only one type of gametes with genotype, Ab.
So the genotype of F1 hybrid is AaBb with brown phenotype.
F1= Brwon (AaBb)
F1 x F1 = AaBb x AaBb
AB | Ab | aB | ab | |
AB | AABB (brown) | AABb (brown) | AaBB (brown) | AaBb (brown) |
Ab | AABb (brown) | AAbb (green) | AaBb (brown) | Aabb (green) |
aB | AaBB (brown) | AaBb (brown) | aaBB (red) | aaBb (red) |
ab | AaBb (brown) | Aabb (green) | aaBb (red) | aabb (red) |
F2 phenotypic ratio = Brown : Green : Red = 9:3:4
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