Question

A plant thought to be heterozygous for two independently assorting genes (Pp; Qq) was selfed and...

A plant thought to be heterozygous for two independently assorting genes (Pp; Qq) was selfed and the progeny were: 188 P_Q_ 24 pp qq 45 pp Q_ 52 P_qq. Do these results support the hypothesis that the original plant was Pp Qq?

Homework Answers

Answer #1

we know that highest number progeny are due to non-recombinant gametes, and lower number of progeny are due to recombinant gametes.

in the question, 188 P-Q- and 52 P-qq can be considered as parental genotypes. (however, usually we find these two numbers closely). By looking at the second one (P-qq), we can say that one gamete has 'P' is associated with 'q'. therefore, one recombinant gamete from parents is 'Pq'

the other two progeny, 24 ppqq and 45 ppQ- are the recombinant ones, ie, these progeny are formed due to fertilization between non-recombinant gametes. by looking at the first one (ppqq), we can say that 'p' is associated with 'q' in recombinant gamete. therefore, the non-recombinant gamete would have 'pQ' genotype.

hence, the original parent would be PpQq.

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