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What is the value of Vi when Vmax is equal to 250 μmol/L/min and KM is...

What is the value of Vi when Vmax is equal to 250 μmol/L/min and KM is equal to four times the substrate concentration?

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Answer #1

This calculation can be solved by using Michaelis menten equation for Enzyme kinetics. We can se that the value for Vmax is given and Km = 4(s).

Km is the substrate conccetration at which the reaction rate is half of its maximum value i.e. 1/2 Vmax.

so, by putting these values in Michaelis Menten equation,

Vi= Vmax(S)/ (S)+ Km

= 250*(S)/(S)+4(S)

=250(S)/5(S)

= 50 μmol/L/min.

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