Null hypothesis - F and C genes show independent assortment.
P0 : FFCC × ffcc
F1 : FfCc
F2 : FfCc × ffcc
Gametes | fc |
FC | FfCc |
Fc | Ffcc |
fC | ffCc |
fc | ffcc |
Expected phenotypic ratio = 1 : 1 : 1 : 1
Total # progenies = 64 + 44 + 86 + 56 = 250
Expected # = 250 / 4 = 62.5
Chi square test -
Phenotype | #observed | #expected | (O-E)^2/E |
Yellow entire | 64 | 62.5 | 0.036 |
Yellow fringed | 86 | 62.5 | 8.836 |
White entire | 56 | 62.5 | 0.676 |
White fringed | 44 | 62.5 | 5.476 |
Calculated chi square value = 0.036 + 8.836 + 0.676 + 5.476 = 15.024
DOF = 4 - 1 = 3
P value is less than 0.01.
Null hypothesis rejected.
Conclusion - genes do not show indpendent assortment and may follow mendelian inheritance.
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