Question

a. Write the genotypes of both parents (the parental cross) who are heterozygous for all four genes or loci (i.e. tetrahybrid cross).

b. Write the genotype of a child (from the cross above in Question a) who has the minimum number of active alleles possible.

c. What are the TRCs for the parents and their child above (assume that the child is a male)?

Parents:

Male Child:

d. Calculate the probability that these parents (above in a) would produce a child with a single active allele assuming independent assortment of the 4 loci. Show your calculations.

This is exactly how the questions are given to me. There is no additional data or information that I have left out. Please explain/show working out. I don't understand the questions well and I've seen other people ask and other answers and they're all different.

Answer 1

A .

(a) aabbccdd

(b) AaBbCcDd

(c) AABBCCDD

(d) AaBBccDd

(e) AaBBCCdd

B.p(AaBbccdd)

=1/4×1/2×1/4×1/2

C. Male -90

Female-76

In solving problems 1-4, you made some predictions of TRCS based on the genotypes of the individuals involved. Suppose we could measure the TRCS for some people with those genotypes and found the actual values to be different from those predicted by your calculations. How would you explain these discrepancies? These discrepancies might be due to the influence of other genes rather than the 4 genes focused in calculation. Basically there are 7 genes affecting the ridge count, however only genes were consider having the highest level of influence.

D.