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Explain(showing each steps in the calculation)you will prepare 1 L of 0.1 M HCL from 1...

Explain(showing each steps in the calculation)you will prepare 1 L of 0.1 M HCL from 1 L of 37% HCL.Molecular weight of HCL is 36.5 g/mol and the density is 1.2 g/ml
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Answer #1

To prepare 1L of 0.1M HCL from 37% HCL we need to first calculate the molarity of 37% HCL.

1. Molarity of 37% HCL :

1.2 g/ml * 1000ml * (0.37/36.5g/mol) = 12.1643 Molar
12 moles of HCL in 1 liter of solution makes 37% HCL

2. Now we can use the formula
M1V1= M2V2
Moles before dilution = Moles after dilution

Required molarity ( M2 )= 0.1M
Required Volume (V2) = 1L = 1000ml
Initial molarity( M1)= 12.1643M
Initail volume (V1) is to be calculated.

Therefore, V1 = M2V2/M1
V1 = 0.1*1000ml/ 12.1643 = 8.22077ml

You should add 8.2207 ml of 37% HCl to make 0.1 M HCL solution

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