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How will Vmax and Km change when enzyme concentration is reduced by 1/2? Increased by 1/2?

How will Vmax and Km change when enzyme concentration is reduced by 1/2? Increased by 1/2?

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Answer #1

Vmax will be reduced by 1/2 when enzyme concentration is reduced by 1/2.

Also, Vmax will be increased by 1/2 when enzyme concentration is increased by 1/2.

Km will remain unchanged in both the cases.

Vmax and Km are derived from the Michaelis Menton kinetics. The rate constants are obtained from the forward and backward reactions. The rate constant is independent of enzyme concentration. The reaction rate is dependent on enzyme concentration.

The change in enzyme concentration will change only the rate of the reactionband hence the velocity. Km is the intrinsic property of enzyme which will remain same for all the concentration.

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