How many different phenotypical combinations are possible using just 5 traits?
The When we cross AaBb with AaBb ( dihybrid cross).
we get 4 diff phenotypic combinations for a trihybrid cross we get 8 different phenotypes.
so the formula is 2 to the power n.
if 5 traits are there nos of phenotype will be 2 to the power 5 and 32. nos of phenotype for n number of traits is 2 to the power n so for 5 traits its 32.
nos of phenotype = 2 to the power n .
(n= nos of traits).
nos of phenotype = 2 to the power 4 is 16.
hence for pentahybrid cross it's 32.
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