Question

Enzyme efficiency is measured by KM                  b. kcat/ KM                 &n

  1. Enzyme efficiency is measured by
    1. KM                  b. kcat/ KM                   c. kcat               d. ½ Vmax
  1. The KM values in mM for a hexokinase with different substrates is:

glucose = 3.4       fructose =2.3            galactose = 0.5            gulose = 1.3

The highest activity for the enzyme takes place with the substrate

  1. glucose            b. fructose           c. galactose                     d. gulose

Homework Answers

Answer #1

Enzyme efficiency is measured by (b) Kcat / KM .

The Kcat is the number of reactions that can occur by a single enzyme per unit second of time in proper conditions , whereas the km is the Michaelis Menton constant which is the concentration of the substrate at which the reaction velocity is half it's maximal velocity.

The lower the value of km ,the higher will be the affinity of the enzyme to the substrate ,so the rate of the reaction is higher with the substrate which having the least value of the km value .

In the given substrates the galactose having the least value that is 0.5 so the fastest activity of the enzyme hexokinase is with the galactose .  

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The enzyme hexokinase acts on both glucose and fructose. The Km and Vmax values are given...
The enzyme hexokinase acts on both glucose and fructose. The Km and Vmax values are given in the table. Using these data, compare and contrast the interaction of hexokinase with both of these substrates. Assume that [E]t is the same for both cases. Substrate Km(M) Vmax(relative) Glucose 1.0X10-4 1.0 Fructose 7.0X10-4 1.8
The N enzyme and its two substrates, D and W a. Use the following datat and...
The N enzyme and its two substrates, D and W a. Use the following datat and the attached graph paper to determine Km and Vmax for the N hydrolysis of its D substrate and of its W substrate. b. Choose ONE substrate and use the following data to determine Km and Vmax from a linear graph, then calculate the Kcat and Kcat/Km if the enzyme concentration is 1.5ng/microliter. c. For which of these two substrates does the N enzyme have...
The following parameter(s) of an enzyme-catalyzed reaction depend(s) on enzyme concentration: A) Km (Michaelis constant) B)...
The following parameter(s) of an enzyme-catalyzed reaction depend(s) on enzyme concentration: A) Km (Michaelis constant) B) Vmax (maximum velocity) C) kcat (turnover number) D) A and B E) B and C Km is the equivalent of: A) Substrate concentration at Vo B) Substrate concentration when Vmax is reached C) Substrate concentration when 1/2 Vmax is reached D) Product concentration when 1/2 Vmax is reached
kcat/Km is alternatively referred to as a second order rate constant and as a specificity constant....
kcat/Km is alternatively referred to as a second order rate constant and as a specificity constant. a) Why is this? Hint: consider [S] << Km b) After testing your favorite enzyme — despacitoase — with two substrates at an enzyme concentration of 10 nM, you obtain Vmax values of 100 µM•s-1 and 10 µM•s-1 and Km values of 100 µM and 20 µM for substrates Fonsi and Bieber, respectively. For which of these substrates is despacitoase more specific?
9. A.  Vmax is a poor metric for indicating enzyme efficiency because: 1) It changes as a...
9. A.  Vmax is a poor metric for indicating enzyme efficiency because: 1) It changes as a result of using competitive inhibitor 2) The total enzyme concentration affects the value of Vmax 3) It requires measuring enzyme velocity 4) It is independent of the total enzyme concentration 5) It varies as a function of the KM value of the substrate B. What is the main disadvantage of using kcat to compare the efficiencies of enzymes? What is the main advantage of...
What do the following kinetic parameters measure in enzyme reactions? a) KM b) kcat c) kcat/KM...
What do the following kinetic parameters measure in enzyme reactions? a) KM b) kcat c) kcat/KM How do you know you are at the “steady state” (measuring initial velocities) when studying an enzyme reaction?
An enzyme is discovered that converts substrate A to product B. The molecular weight of the...
An enzyme is discovered that converts substrate A to product B. The molecular weight of the enzyme is 10000 Daltons. The Km and Vmax values for the enzyme are shown below: Km (mM) 2 Vmax (mmole/min/mg) 20 What is the reaction initial velocity for this enzyme when the concentration of A is 4 mM? What is the turnover number of this enzyme?
An enzyme catalyzes the reaction A --> B. The enzyme is present at a concentration of...
An enzyme catalyzes the reaction A --> B. The enzyme is present at a concentration of 2 nM, and the Vmax is 1.2 mm/s. The Km for substrate A is 10 mM. Calculate the initial velocity of the reaction, Vo, when the substrate concentration is a) 4 mM, b) 15 mM, c) 45 mM.
The zero order rate is seen in an enzyme catalyzed reaction when: A. There is too...
The zero order rate is seen in an enzyme catalyzed reaction when: A. There is too much enzyme and too little substrate B. Enzyme reactions are always first order C. The Michaelis constant is very high D. The Vmax of the reaction is twice that which is observed E. The enzyme substrate comples is at its maximum concentration What happens when you add more enzyme to a catalyzed reaction that already is proceeding at Vmax? A. The reaction is inhibited...
18. KM is— A) an indicator of how strongly an enzyme binds its substrate. B) the...
18. KM is— A) an indicator of how strongly an enzyme binds its substrate. B) the rate at which the enzyme binds the substrate. C) the rate constant for the reaction ES ® E + P. D) a measure of enzyme efficiency. E) a measure of substrate turnover.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT