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Suppose a DNA has the equal amounts of A, G, C and T and the nucleotides...

Suppose a DNA has the equal amounts of A, G, C and T and the nucleotides appeared at random. What is the average distance between two stop codons? a.about one in every 10 codons b.about one in every 100 codons c.One in every 3 codons d.about one in every 21 codons

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Answer #1

The DNA sequence has equal number of A, T, G and C. Hence, they should be present as 25%. GC content will therefore be 50%.

DNA is transcribed to mRNA for protein synthesis. Each set of triplet nucleotide is a codon. AUG is the start codon that codes for methionine. There are a total of 64 codons. Of these 64 codons, there are 3 stop codons UAA, UAG and UGA in mRNA. Hence the average distance between two codons in the random DNA (where the nucleotides can appear) = 64/3= 21.

The option is d. The average distance between 2 stop codons is one in every 21 codons.

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