Suppose a DNA has the equal amounts of A, G, C and T and the nucleotides appeared at random. What is the average distance between two stop codons? a.about one in every 10 codons b.about one in every 100 codons c.One in every 3 codons d.about one in every 21 codons
The DNA sequence has equal number of A, T, G and C. Hence, they should be present as 25%. GC content will therefore be 50%.
DNA is transcribed to mRNA for protein synthesis. Each set of triplet nucleotide is a codon. AUG is the start codon that codes for methionine. There are a total of 64 codons. Of these 64 codons, there are 3 stop codons UAA, UAG and UGA in mRNA. Hence the average distance between two codons in the random DNA (where the nucleotides can appear) = 64/3= 21.
The option is d. The average distance between 2 stop codons is one in every 21 codons.
Get Answers For Free
Most questions answered within 1 hours.