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A couple is heterozygous for two genes, cystic fibrosis (CF) and albinism, what is the probability...

A couple is heterozygous for two genes, cystic fibrosis (CF) and albinism, what is the probability of their first child having either CF or albinism?
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Answer #1

Albinism and cystic fibrosis are two independent diseases.

Parents are heterozygous (carriers) for CF and for Alb

CF = normal, cf = cystic fibrosis, A = normal (no albinism) and a = albinism

Cystic fibrosis:

Parents   Cf cf x Cf cf

In F1 generation - 1/4 Cf Cf : 1/2 Cf cf : 1/4 cfcf   

Phenotype - 3/4 normal : 1/4 CF disorder

Albinism:

Parents Aa x Aa

In F1 generation - 1/4 AA : 1/2 Aa : 1/4 aa

Phenotype - 3/4 normal : 1/4 albinism disorder

When combining CF or albinism then the probability of one or the other is the addition of the separate probabilities 1/4 for CF + 1/4 for Albinism = 1/2.

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