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A trihybrid pea plant, having the genotype AaBbC1C2, is self-fertilized. All loci are unlinked. There is...

A trihybrid pea plant, having the genotype AaBbC1C2, is self-fertilized. All loci are unlinked. There is complete dominance at the A and B loci but incomplete dominance at the C locus. The fraction of progeny that will be phenotypically different from the parent is ​? explain

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Answer #1

Answer: 23/32

The three loci will assort independently. To answer this question, consider each locus separately. First, in a cross of Aa x Aa, 3/4 will show the dominant phenotype like the parents. The same is true of the B locus. Since the C locus displays incomplete dominance, however, only 1/2 of the offspring will be heterozygotes like the parent.

The fraction of all progeny that will be phenotypically the same as the parent will be the product of the individual probabilities: 3/4 x 3/4 x 1/2 = 9/32.

The proportion that will be phenotypically different is the remainder of all combinations: 1 − 9/32 = 23/32.

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