Energy expended to drive cyclosis in a single chloroplast cell
Use the formula (Equation 1) derived in the practical module (included below) to calculate the energy expended to bring about cyclosis in each of the cells of the leaves you have been observing. Don’t forget units! Use brackets around each variable when performing your calculations.
You must show your working to gain full marks.
Equation 1: 6πrnV2M (Js-1 Cell-1 for a cell containing M chloroplasts) |
π |
3.14 (pi) |
r |
3.665 x 10-6 (your mean radius) |
n |
10-2 Ns m-2 (viscosity for cytoplasm) |
V |
5.0 x10-6 m/s |
M |
37 (your mean chloroplast number) |
Working: 6 x 3.14159 x 3.665 x 10-6 x 10-2 Ns m-2 x 5.0 x 10-6 2 x 37 = 1.278045936 x10-40 I would like to double check my answer, i don't know what to do with Ns m-2 . |
From the data given in the question:
π = 3.14
r = 3.665 x 10-6
n = 10-2 Ns m-2
V= 5 x 10-6 m/s
M = 37
Using the equation
E = 6π rn v2M
E = 6 x 3.14 x 3.665 x 10-6 m x 10-2 Ns m-2 x (5 x 10-6 m/s)2 x 37
E = 6 x 3.14 x 3.665 x 5 x 5 x 37 x 10-6 m x 10-2 Ns m-2 x 10-6 m/s x 10-6 m/s
E = 63870 x 10-20 N m x m x m x s/m x m x s x s
E = 6.387 x 10-16 N m/s
E = 6.387 x 10-16 J/s/ cell ( 1 N m = 1 J)
Hope it is clear
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