Question

Choose the correct answer: When Mendel crossed a plant homozygous for round seeds to another plant...

Choose the correct answer:

When Mendel crossed a plant homozygous for round seeds to another plant homozygous for wrinkled seeds, he found that all the progeny had round seeds. How is this explained?

a) The allele for round seeds is dominant to the allele for wrinkled seeds.

b) The progeny were homozygous for the allele for round seeds.

c) The parent that was homozygous for round seeds underwent self-pollination.

d) Segregation of alleles in the two parents produced gametes with both alleles.

e) The allele for round seeds is recessive to the allele for wrinkled seeds.

Homework Answers

Answer #1

The answer is a. The allele for round seeds is dominant to the allele for wrinkled seeds.

As the pure homozygous plants are crossed, they produce only one type of gametes. When these gametes produce the offspring, only dominant allele exhibits her character. On the basis of this mendal proposed his first law i.e. Law of Dominance.

Here the both are homozygous plants, and produced offspring will be in heterozgyous in condition. So, the dominant character will be expressed in the offspring.

Find the below image for explanation...

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Round pea seeds are dominant to wrinkled seeds. If a homozygous round seed plant is crossed...
Round pea seeds are dominant to wrinkled seeds. If a homozygous round seed plant is crossed with a homozygous wrinkled seed plant, all the offspring will be heterozygous. Suppose you cross two of the heterozygous offspring and produce 400 offspring in the next generation. How many of these would have wrinkled seeds? How many would have round seeds?
In a Mendelian cross, a red flowering heterozygous male plant is crossed with a white flowering...
In a Mendelian cross, a red flowering heterozygous male plant is crossed with a white flowering homozygous female plant. Most of the children of this cross (generation F1) produce red flower. 1) In this crossing by the progeny produced we can conclude that the recessive allele is: a-produce white flower b-produce red flower c-produce pink flower d-the recessive allele cannot be determined 2) phenotype of the female parent plant is: a-produce red flower b-homozygous dominant c-homozygous recessive d-produce white flower...
QUESTION 1 :The alleles of a particular gene segregate independently into individual gametes (sex cells) during...
QUESTION 1 :The alleles of a particular gene segregate independently into individual gametes (sex cells) during meiosis. True or False QUESTION 2:The DNA sequence of a gene is a phenotype. True or False QUESTION 3:Two diploid individuals, one homozygous and the other heterozygous at a particular gene, make babies. Which of the following statements about the offspring genotype is correct? (Hint: draw Punnett squares) A. All offspring are heterozygotes B. All offspring are homozygotes C. 1/2 of the offspring are...
A phenotypically wilptype F1 female fruit fly that was heterozygous for genes controlling body color and...
A phenotypically wilptype F1 female fruit fly that was heterozygous for genes controlling body color and wing length was crossed to a homozygous mutant male tester with black body (mutant allele b) and vestigial wings (mutant allele vg). a. Symbolize the genotype of the dihybrid female and tester male using appropriate Drosophila gene symbolism using b+ and vg+ for the wildtype dominant alleles; b and vg for the recessive mutant alleles. b. What is the genotype of the F1 dihybrid...
The expression of yellow petals in sunflowers is due to the dominant allele Y. The homozygous...
The expression of yellow petals in sunflowers is due to the dominant allele Y. The homozygous recessive (y) has orange petals. Plant height is controlled by another gene with two alleles, T and t, with Tall (T) being dominant to short (t). Two individuals that are heterozygous for both traits are crossed, the number of offspring of each phenotype is recorded in the table below. 1. The assumption is that these two genes assort independently. To test this, complete a...
1. A species of flowering plant includes plants with blooms that range from bright golden yellow...
1. A species of flowering plant includes plants with blooms that range from bright golden yellow to very pale yellow; no flowers carrying the yellow pigment allele appear white. The allele for yellow flower color: a. must be a suppressor of another allele. b. demonstrates incomplete penetrance. c. demonstrates variable expressivity. d. must be a modifier of another allele. e. demonstrates variable penetrance. 2. Coat color in mice is determined by two alleles acting at a single locus: B is...
11. Compare and contrast DNA and RNA. 12. During prophase I, the pairing of homologous chromosomes...
11. Compare and contrast DNA and RNA. 12. During prophase I, the pairing of homologous chromosomes results in the formation of a ______. a. cell plate b. centrosome c. zygote d. chromatid e. tetrad 13. During telophase ______. a. tetrads form b. the events of prophase are reversed c. sister chromatids separate d. chromosomes line up on the midline of the cell e. the genetic material doubles 14. Which of the following occurs during prophase? a. The mitotic spindle begins...
Having freckles is a dominant trait. A person is heterozygous for having freckles. Their genotype is...
Having freckles is a dominant trait. A person is heterozygous for having freckles. Their genotype is _________ and their phenotype is _________. [ Choose the choice with the answers in the correct order. ] * Freckles, Ff ff, freckles freckles, no freckles Ff, Freckles A fertilized egg created through sexual reproduction ______________. * is genetically identical to the parents contains genetic material from only one parent is genetically identical to other eggs of the same parents has a combination of...
1 One form of Retinitis Pigmentosa is a Y- linked genetically inherited disease of the eye...
1 One form of Retinitis Pigmentosa is a Y- linked genetically inherited disease of the eye in which the cells of the retina produce defective. Symptoms include a progressive loss of sight starting with decreased night vision, loss of peripheral vision, and eventually blindness. If a father has the disease and a woman who does not, have a son what are the chances their son will also have the disease? A) not enough information B) 25% C) 0% D) 50%...
For problem 1, to compute probabilities, the probability of event 1 AND event 2 is obtained...
For problem 1, to compute probabilities, the probability of event 1 AND event 2 is obtained by multiplying the two probabilities together, whereas the probability of event 1 OR event 2 is obtained by adding the two probabilities. 1. Duchenne muscular dystrophy (DMD) is a condition that causes muscle degeneration and then death. Most people with the condition are wheelchair-bound by age 12 and dead before age 30. The condition is due to a mutation in the gene for a...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT