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If the human haploid genome contains 3x109 bp, and a repetitive sequence, of 35 bp in...

If the human haploid genome contains 3x109 bp, and a repetitive sequence, of 35 bp in length, is present 150,000 times, then what will be the copy number of the repeat in the human diploid genome?

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Answer #1

# of repeats present in haploid human genome (3 × 10^9) = 150,000

# of repeats present in diploid human genome (6 × 10^9) = 150,000 × 2 = 300,000

Answer is 300,000.

Repetitive sequences are set of nucleotides which are repeated in the genome multiple times. They can be tandemly arranged, one after the other or they can be interspersed (scattered) in the genome.

Every individual have a specific number of repeats of any sequence and therefore these sequences can be used as molecular markers.

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