Albinism is due to a recessive gene.
a. Give the results (the genotypes, phenotypes, and their respective frequencies) of a classic Mendelian cross between a mouse with albinism and another mouse homozygous for pigmented coat color. This is the F1 generation.
b. Give the results of a cross between 2 mice of the F1 generation: what are the expected phenotypic ratio and the expected genotypic ratio?
Please find the answers below:
Answer a: According to the information, the cross is made between an albino (aa) and a normal (AA) mice. Thus, the Punnett square can be formulated as below:
a | a | |
A | Aa | Aa |
A | Aa | Aa |
Genotye: All Aa
Phenotype: All normal colored
Frequency: 50% for allele A and 50% for allele a.
Answer b: According to the information, the cross has been made between two individuals of F1 generation i.e. Aa*aA. Thus, the Punnett square can be formulated as below:
A | a | |
A | AA | Aa |
a | Aa | aa |
Genotype frequency: AA : Aa : aa :: 1:2:1
Phenotype frequency: Normal : albino : 3:1
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