The rabbit (Oryctolagus cuniculus) has a diploid number of 44. How many chromosomes will be present in the following cell types:
a. First polar body
b. Primary spermatocyte
c. Spermatozoa
d. Oogonium
a. First polar body
As it is the result of first meiosis and as the chromosome
segregation occurs in meiosis I it results hapolid condition,so,
22
chromosomes will be there in first polar body.
b. Primary spermatocyte
As the primary spermatocyte is in dipoloid condition 44 chromosomes
are present.
c. Spermatozoa
As it is the result of complete meiosis and as the chromosome
segregation and chromatid segregation occurs in meiosis it results
hapolid condition,so, 22 chromosomes
will be there in spermatoza.
d. Oogonium
The starting cell of the primary oocyte is reffered as oognium. As
it is in dipoloid condition 44 chromosomes
are present.
Get Answers For Free
Most questions answered within 1 hours.